已知n阶矩阵A满足 A^2(A-2E)=3A-11E,证明A+2E可逆,并求(A+2E)^-1_作业帮
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已知n阶矩阵A满足 A^2(A-2E)=3A-11E,证明A+2E可逆,并求(A+2E)^-1
已知n阶矩阵A满足 A^2(A-2E)=3A-11E,证明A+2E可逆,并求(A+2E)^-1
因为 A^2(A-2E)=3A-11E所以 A^3-2A^2-3A+11E=0所以 A^2(A+2E)-4A(A+2E)+5(A+2E)+E=0所以 (A^2-4A+5E)(A+2E)=E所以 A+2E 可逆, 且 (A+2E)^-1 = A^2-4A+5E数列{a n }(n∈N ﹡ )中,a 1 =0,当3a n &n 2 时，a n+1 =n 2 ,当3a n &n 2 时，a n+1 =3a n .求a 2_百度知道
数列{a n }(n∈N ﹡ )中,a 1 =0,当3a n &n 2 时，a n+1 =n 2 ,当3a n &n 2 时，a n+1 =3a n .求a 2
a n+1 =3a n ;n 2 时，a n+1 =n 2 ,当3a n &n 2 时,当3a n &lt，a 4
数列{a n }(n∈N ﹡ )中,猜测数列的通项a n 并证明你的结论，a 5 ,a 1 =0.求a 2 ，a 3
提问者采纳
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出门在外也不愁已知数列a(n+1)=(-1)^n*a(n)+a,a4=4-a,且a1+a4=3a2,求a的值_作业帮
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已知数列a(n+1)=(-1)^n*a(n)+a,a4=4-a,且a1+a4=3a2,求a的值
已知数列a(n+1)=(-1)^n*a(n)+a,a4=4-a,且a1+a4=3a2,求a的值
a2=-a1+aa3=a2+a=-a1+2aa4=-a3+a=a1-2a+a=a1-a=4-aa1=4a1+a4=3a2a1+a1-a=3(-a1+a)8-a=3(-4+a)整理,得4a=20a=5数列{a n }(n∈N ﹡ )中,a 1 =0,当3a n &n 2 时，a n+1 =n 2 ,当3a n &n 2 时，a n+1 =3a n .求a 2_百度知道
数列{a n }(n∈N ﹡ )中,a 1 =0,当3a n &n 2 时，a n+1 =n 2 ,当3a n &n 2 时，a n+1 =3a n .求a 2
a n+1 =3a n ;n 2 时，a n+1 =n 2 ,当3a n &n 2 时,当3a n &lt，a 4
数列{a n }(n∈N ﹡ )中,猜测数列的通项a n 并证明你的结论，a 5 ,a 1 =0.求a 2 ，a 3
提问者采纳
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