d^3 5d^2 8d 3=0他们的和

已解决问题
用劳斯判据判定该系统的稳定性&D(s)=s^6+3s^5+4s^4+2S^3+3s^2+4s+5=0
提问时间: 02:41:06
浏览次数:8558
该答案已经被保护
例3-5 已知线性系统的闭环特征方程为D(s)=s4+2s3+3s2+4s+5=0,试用劳斯稳定判据判别系统的稳定性 解:按表3-3所示规律,得劳斯表如下 s4 1 3 5 s3 2 4 s2 1 5 s1 -6 0 s0 5 由于劳斯表第一列元符号变化两次,系统有两个正实部根,该系统不稳定。&br/&&br/& (2)劳斯稳定判据的特殊情况 应用劳斯判据建立的劳斯表,有时会遇到两种情况,使计算无法进行,因此需要进行相应的数学处理,而处理的原则是不影响劳斯稳定判据的判断结果。&br/&&br/& 劳斯表中出现全零行 若系统存在对称坐标原点的极点时会出现全零行这种情况。
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http://share.v.t.qq.com/index.php?c=share&a=index&title=%23QQ%E9%A3%9E%E8%BD%A6%E6%8A%BD%E5%A5%96%E7%A7%92%E6%9D%80%E5%99%A8%E5%85%8D%E8%B4%B9%E4%BA%86%23+%23%E6%8E%A8%E8%8D%90%E6%94%B6%E5%90%AC%23%20%E2%86%92%E3%80%8E%40tangyanhong%E3%80%8F%E4%B8%BA%E4%BA%86%E6%84%9F%E8%B0%A2%E5%B9%BF%E5%A4%A7%E7%94%A8%E6%88%B7%E5%AF%B9%E6%9C%AC%E8%BD%AF%E4%BB%B6%E7%9A%84%E4%BF%A1%E4%BB%BB%EF%BC%8C%E4%BD%9C%E8%80%85%E5%86%B3%E5%AE%9A%E6%8E%A8%E5%87%BA%E2%80%9C%E6%8A%BD%E5%A5%96%E7%A7%92%E6%9D%80%E5%99%A8%E2%80%9D%E7%9A%84%E5%85%8D%E8%B4%B9%E7%89%88%E6%9C%AC%EF%BC%81%E6%83%B3%E6%8B%A5%E6%9C%89%E6%B0%B8%E4%B9%85A%E8%BD%A6%E5%90%97%EF%BC%9F%E6%83%B3%E6%8B%A5%E6%9C%89%E7%BB%9D%E7%89%88%E8%A3%85%E5%A4%87%E5%90%97%EF%BC%9F%E9%82%A3%E5%B0%B1%E5%BF%AB%E6%9D%A5%E4%B8%8B%E8%BD%BD%3Ahttp%3A%2F%2Fmiaoshaqi.ys168.com%2F++++++++%23%E5%88%86%E4%BA%AB%E8%A7%86%E9%A2%91%23&url=http%3A%2F%2Fwww.tudou.com%2Fprograms%2Fview%2FTs-W4CzEZZI%2F%3FresourceId%3D_02_99&appkey=&site=www.jiathis.com&pic=
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content-length: 8238
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set-cookie: __hash__=899d4dd0bfade8b5277c8cbab57a6ca2; expires=Tue, 27-Oct-:00 GMT; path=/; domain=share.v.t.qq.com
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server: nginx/1.5.7
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date: Mon, 26 Oct :00 GMT
p3p: CP=CURa ADMa DEVa PSAo PSDo OUR BUS UNI PUR INT DEM STA PRE COM NAV OTC NOI DSP COR
content-type: text/ charset=utf-8
Response content SHA256
f00d35d323dd08db35c54ccffd8a7c4910
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Username or email> 问题详情
以下数组定义中不正确的是()。
A.int a[2][3]:
B.int b[][3]={0,1,2,3};
C.int c[100][100]={0};
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提问人:匿名网友
发布时间:
以下数组定义中不正确的是(&&)。&&A.int a[2][3]:&&B.int b[][3]={0,1,2,3};&&C.int c[100][100]={0};&&D.int d[3][]={{1,2},{1,2,3},{1,2,3,4}};
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单项选择题以下语句定义正确的是(
)。A.int a[1][4]={1,2,3,4,5};B.float a[3][]={{1,2},{2,3},{3,1}};C.long a[2][3]={{1},{1,2},{1,2,3},{0,0}};D.double a[][3]={8};
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