你画我猜题目大全图如图 谢谢

题目如图,请解答,谢谢。_百度知道
题目如图,请解答,谢谢。
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来自中国石油大学(北京)
沈普宁&&教师
孙晓丽&&学生
丁璐&&学生
吴淑忠&&学生
韦婉娟&&学生如图,看图回答问题,谢谢!_百度知道
提问者采纳
1.It&#39;s windy.2.It&#39;s sunny.3.It&#39;s cloudy.4.It&#39;s rainy.
She&#39;s reading a book.
提问者评价
太给力了,你的回答完美解决了我的问题!
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出门在外也不愁高中数学,题目如图,急求详细过程,谢谢_百度知道
高中数学,题目如图,急求详细过程,谢谢
jpg" esrc="http,baidu,,hiphotos,
提问者采纳
4.--------------------------(12分)
化简可得f(x)=7+4√3cosB+2cosx--------------------------(2分)
f(2B)=7+4√3cosB+2cos2B=14,(Ⅰ)由题意可得f(x)=,2)=7+4√3cosB&#,字好难打,2sinB=1
同除(cosB)^2可得
[(tanB)^2&#8722,sinB&#8722,解,
整理得,3√3&#47,4√3tanB+12]&#47,
∵∠B是锐角,4cos2B+4√3cosB&#8722,2或cosB=&#sinBcosB+12(cosB)^2=9,9=0--------------------------(4分)
解得cosB=√3&#47,2=1
∴AC=1--------------------------(6分)
(Ⅱ)由(Ⅰ)可得f(B+π&#47,√3±3)&#47,4,^2+2cosx=4+3+2×2×3cosB+2cosx,2BC&#8226,解得tanB=(&#8722,BAcosB=4+3&#cosB=3--------------------------(8分)
将上式平方得,4√3×√3&#47,打了N久),[(tanB)^2+1]=9--------------------------(10分)
整理得,[(sinB)^2+(cosB)^2] =9,(sinB)^2&#8722,
∴[(sinB)^2&#sinBcosB+12(cosB)^2]&#47,2(舍去)
∴AC2=BC2+BA2&#8722,∴tanB=(3&#8722,√3)&#47,BC+BA,8(tanB)^2+4√3tanB&#8722,
同除cosB后面那个式子怎么得到的,画不出来
提问者评价
太给力了,你的回答完美地解决了我的问题,非常感谢!
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com/zhidao/pic/item/71cf3bc79f3df8dc4ad39eefcee5,,hiphotos,
cos替换了,那sin是怎么约掉的?
提取公因式(cosB)^2,然后再将(cosB)^2代换掉即可。
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出门在外也不愁求一篇英文作文!题目如图!万分感谢!谢谢!!_百度知道
提问者采纳
Remember to wrap it up, Everybody is welcome, The party will be held in the playground , sign your name and write a few words of wishes,The Student Union, dancing, There will be music,30, It will begin at 7,Don’t forget, August 15th, singing, There’s sure to be a lot of fun, 7, games and exchange of gifts, to welcome our friends from America, playground ,NoticeThe Student Union is going to hold a party on Saturday evening,30 pm, Please bring a small gift for this purpose,
提问者评价
太给力了,你的回答完美的解决了我的问题!
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dear American friends!This is school broadcast station, Union will hold an evening party tomorrow evening for you,To increase the communication between us and help you know better about our school,we are sincerely looking forward to your participation!Wish you can all have fun!,the Students&#39,There will be lots of excelent activities there and you can ask anything you&#39,d like yo know,Pay attention now,
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