1.Find the equation of the tangent to the curve y=x^2,which is parallel to the x-axis2.Find the equation of the tangent to the curve y=x^2-2x which is perpendicular to the line 2y=x-13.Find the equation of the normal to the curve y=3x^2-2x-1 which is_百度作业帮
拍照搜题，秒出答案
1.Find the equation of the tangent to the curve y=x^2,which is parallel to the x-axis2.Find the equation of the tangent to the curve y=x^2-2x which is perpendicular to the line 2y=x-13.Find the equation of the normal to the curve y=3x^2-2x-1 which is
1.Find the equation of the tangent to the curve y=x^2,which is parallel to the x-axis2.Find the equation of the tangent to the curve y=x^2-2x which is perpendicular to the line 2y=x-13.Find the equation of the normal to the curve y=3x^2-2x-1 which is parallel to the line y=x-3
1：找到平行于X轴的曲线切线方程Y = X^ 22：找到的垂直于线路2Y= X- 1的切线方程曲线Y = X ^ 2- 2X3：找到平行于线Y = X - 3的正常曲线方程Y =3X^ 2- 2X- 1
1。找到方程曲线的切线方向y = x ^ 2 x轴平行2。找到方程曲线的切线方向y = x ^ 2-2x,垂直于y = x-1线23。找到方程曲线的正常x ^ 3 y = 2-2x-1是直线平行y=x=-3,
图呢？？？？？？？
1.找到方程的切线，曲线 y = x ^2，这是平行于 x 轴2.找到方程的切线，曲线 y = x ^2 2 x 是垂直的线 2y = x-13.找到方程的垂直于曲线 y = 3 x ^2 2 x-1 是平行的线 y = x-3自己算吧！
您可能关注的推广回答者：求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移）of the particle from t=0 to t=4._百度作业帮
拍照搜题，秒出答案
求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移）of the particle from t=0 to t=4.
求一道英文数学题的答案If the position of a particle at a time is given by the equation x(t)=2t^3-9t^2+12t-18Find the distance(距离非位移）of the particle from t=0 to t=4.
对x（t）求导,得到6t^2-18t+12,令这个式子等于0,则有x=1或者2,即x（t）在这两点处取得极值；再根据单调性大致得出波形,x（0）= -18；x（1）= -13；x（2）= -14；x（4）= 14；由波形知距离=|x(1) - x(0)| + |x (2) - x(1)| + |x(4) - x(2)| =34(方法肯定是对的,结果你自己再算下,应该没有错)
求两点（0，-18），（4,14）间距离，结果是4*65½，四倍的六十五开平方
x(t)=2t^3-9t^2+12t-18x(0)=-18x(4)=2*4^3-9*4^2+12*4-18=14x(4)-x(0)=32
您可能关注的推广回答者：求翻译全英文数学题！！_百度知道
求翻译全英文数学题！！
each team plays every other team exactly once.So we have the equation Solving. If a total of 21 conference games were played during the 2012 season?SolutionThis problem is very similar to a handshake problem, how many teams were members of the BIG N conference14.In the. We use the formula
to usually find the number of games played (or handshakes). Now we have to use the formula in reverse, we find that the number of teams in the BIG N conference is , a middle school football conference
each team plays every other team exactly once. Now we have to use the formula in reverse. If a total of 21 conference games were played during the 2012 season?SolutionThis problem is very similar to a handshake problem, how many teams were members of the BIG N conference14;2 to usually find the number of games played (or handshakes). We use the formula n(n-1)&#47.n(n-1)&#47.In theBIG N, a middle school football conference
提问者采纳
We use the formula
to usually find the number of games played (or handshakes), how many teams were members of the BIG N conference。如果在2012赛季总共比了21次.14.In theBIG N. Now we have to use the formula in reverse。现在我们反着用这个公式，一个中学搞足球比赛.一个中学搞足球比赛？（14。I wonder why……大意为.So we have the equation Solving。我们常用这个公式去找出比赛的次数（或是握手的）, we find that the number of teams in the BIG N conference is ，请问有多少个队参加了这次比赛.N中. If a total of 21 conference games were played during the 2012 season，每个队只跟别的每一个队比赛一次。如果在2012赛季总共比了21次, each team plays every other team exactly once这个应该是题目做法解析吧;2去找比赛的次数，每个队只跟别的每一个队比赛一次？（14, a middle school football conference.）14。现在我们反着用这个公式.在BIG！，但前一个和后一个都有不全的地方.In the：这个问题和握手问题非常相似：14：这个问题跟握手问题非常相似？）（This problem is very similar to a handshake problem，请问有多少个队参加了这次比赛，我们解出队伍的数量为
（为什么就没了啊。我们常用公式n(n-1)&#47, a middle school football conference. If a total of 21 conference games were played during the 2012 season?）解答。n(n-1)&#47, each team plays every other team exactly once。因此我们有了这个方程的解, how many teams were members of the BIG N conference?）解答
提问者评价
其他类似问题
数学题的相关知识
按默认排序
其他1条回答
等待您来回答
下载知道APP
随时随地咨询
出门在外也不愁几道英文题!第37页1.If the equation（方程） m(x-1)=2001-n(x-2) for x has infinite roots（无限个根） ,then m的2001次方+n的2001次方=2.We have the following numbers 9/5，12/7，27/17，36/19，54/29，the maximum (最大的)number_百度作业帮
拍照搜题，秒出答案
几道英文题!第37页1.If the equation（方程） m(x-1)=2001-n(x-2) for x has infinite roots（无限个根） ,then m的2001次方+n的2001次方=2.We have the following numbers 9/5，12/7，27/17，36/19，54/29，the maximum (最大的)number
几道英文题!第37页1.If the equation（方程） m(x-1)=2001-n(x-2) for x has infinite roots（无限个根） ,then m的2001次方+n的2001次方=2.We have the following numbers 9/5，12/7，27/17，36/19，54/29，the maximum (最大的)number among them is (),the minimum（最小的） number is ().3.The admission price per child at an amusement park（游乐园） is 5/9of the admission price(入场费) per adult.If the admission price for 6 adult and 3 children is 276 yuan ,then the admission price per adult is ()A24 B32 C36 D404.The sequence(序列) 1/1,1/2,2/2,1/3,2/3,3/3,4/1,4/2,4/3,4/4,5/1,5/2,等等,then the 2003rd number is () 只知道第四题也行！
036/19,27/17c60/63
回答个问题还要别人自备书籍要求真高
鬼知道你说哪本书
最起码把题发上来呀
您可能关注的推广回答者：}